N^3- , O^2- , F^- , Mg^2+ , Na^+ , Al^3+ Arrange in the increasing order of ionic radii.

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Solution

Each of the given species (ions) has the same number of electrons (10 electrons). Hence, the given species are isoelectronic.
The ionic radii of isoelectronic species increases with a decrease in the magnitudes of nuclear charge. The arrangement of the given species in order of their increasing nuclear charge is as follows: N3–<O2–<F–<Na+<Mg2+<Al3+
Nuclear charge = +7 +8 +9 +11 +12 +13
Therefore, the arrangement of the given species in order of their increasing ionic radii is as follows:
Al3+<Mg2+<Na+<F–<O2–<N3–

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Similar questions

Q. Arrange the following species in the increasing order of their ionic radii, giving reasons.

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Consider the following species: $N^{3 -}, O^{2 -}, F^{-}, N a^{+}, M g^{2 +} a n d A l^{3 +}$
(a)What is common in them?
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Q. Arrange

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Q. Consider the following species :

^{3 -}

, O

^{2 -}

^{-}

, Na

^{+}

, Mg

^{2 +}

and Al

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(a) What is common in them?

(b) Arrange them in the order of increasing ionic radii.

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Increasing order of ionic size

N^{3 -}, N a^{+}, F^{-}, O^{2 -}, M g^{2 +}

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