Let A and B be two matrices different from I such that AB=BA and An–Bn is invertible for some natural number n. If An–Bn=An+1–Bn+1=An+2–Bn+2, then
I. (I–A) is singular
II. (I–B) is singular
III. A+B=AB+I
IV. (I–A)(I–B) is non-singular
A
I, II, III, IV
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B
I, III, IV only
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C
I, II, III only
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D
I, II, IV only
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Solution
The correct option is D I, II, IV only Since matrices A and B are commutative hence I, II, III are true.