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Question

The equation of the common tangents to x2+4y2=8 and y2=4x can be

A
2x+y4=0
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B
2xy+4=0
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C
x2y+4=0
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D
x+2y+4=0
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Solution

The correct option is D x+2y+4=0
Let the tangent be y=mx+1m
x2+4(mx+1m)2=8 has equal roots
m=12,m=12

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