We have taken three different dilute aqueous solutions of 0.1MC6H12O6,0.2MNaCland 0.1MCaCl2 separately then select the correct statement(s) for these solutions.
A
CaCl2 solution will have lowest freezing point.
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B
Order of osmotic pressure of solutions is CaCl2>NaCl>C6H12O6
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C
C6H12O6 solution will have highest vapour pressure.
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D
Order of boiling point of solutions is NaCl>CaCl2>C6H12O6
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Solution
The correct option is D Order of boiling point of solutions is NaCl>CaCl2>C6H12O6 0.01MC6H12O6;i=1⇒i×m=0.1 0.2MNaCl;i=2⇒i×m=0.4 0.1MCaCl2;i=3⇒i×m=0.3 ∴ Colligative properties are related to van’t hoff factor and molality or amount of solute particles.
According to Raoult’s law, when a non-volatile solution is added to the solvent its vapor pressure decreases. (RLVP)=p∘−psps=i.xsolute ∴C6H12O6⇒ Highest vapour pressure
⇒ Elevation in boiling point ↑ΔTb∝i.m↑
Therefore boiling point order NaCl>CaCl2>C6H12O6
⇒ Depression in freezing point ΔTf∝i.m NaCl lowest freezing point.
⇒ Osmotic pressure π=i.CRT
Osmotic pressure order : NaCl>CaCl2>C6H12O6