1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A Carnot engine has an efficiency of 16. When the temperature of the sink is reduced by 62 ∘C, its efficiency is doubled. The temperatures of the source and the sink are respectively

A
99 C,37 C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
124 C,62 C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
37 C,99 C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
62 C,124 C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 99 ∘C,37 ∘CThe efficiency of a Carnot engine is given by, η=1−T2T1 Here, T1 and T2 are temperatures of source and sink, respectively. 16=1−T2T1 16=T1−T2T1 T1=6T1−6T2 ⇒T1=1.2 T2 And, 13=1−T2−62T1 13=T1−T2+62T1 13=1.2T2−T2+621.2T2 1.2T2=0.6T2+186 ∴T2=310 K=27 ∘C ⇒T1=310×1.2=372 K=99 ∘C Hence, (B) is the correct answer.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Second Law of Thermodynamics
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program