On a planet a freely falling body takes 2 sec when it is dropped from a height of 8m, the time period of simple pendulum of length 1m on that planet is
A
3.14
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B
3.1
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C
3
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Solution
Length of the pendulum =1m
On a planet, if a body dropped initial velocity (u=0) from a height h and takes time t to reach the ground then,
h=12gpt2⇒gp=2ht2=2×84=4m/s2 Using T=2π√lgp ⇒T=2π√14=π=3.14sec