Question

Solve the given expression:
$\frac{0\times 1}{1\times (-1)}+\frac{(-1)\times 19}{(-19)\times 1}-\frac{(-91)\times 0}{(-17)\times 1}+\frac{1\times 19}{(-1)\times 19}$

• A. 1
• B. None of the above
• C. 0
• D. $-1$

Answer 1

The correct option is C 0

In the given expression,
$\frac{0\times 1}{1\times (-1)}+\frac{(-1)\times 19}{(-19)\times 1}-\frac{(-91)\times 0}{(-17)\times 1}+\frac{1\times 19}{(-1)\times 19}$
We know that, multiplication of an integer by one results the same integer and division of an integer by zero results in zero.
So, $\frac{0\times 1}{1\times (-1)}=\frac{0}{-1}=0$
$\frac{(-1)\times 19}{(-19)\times 1}=1$
$\frac{(-91)\times 0}{(-17)\times 1}=0$
$\frac{1\times 19}{(-1)\times 19}=-1$
Thus, expression
$\frac{0\times 1}{1\times (-1)}+\frac{(-1)\times 19}{(-19)\times 1}-\frac{(-91)\times 0}{(-17)\times 1}+\frac{1\times 19}{(-1)\times 19}$$=0+1-0-1=0$
The answer of the expression is 0.