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Question

A particle of mass m moves in a circular orbit in a central potential field U(r)=12kr2. If Bohr's quantization conditions are applied, radii of possible orbitls and energy levels vary with quantum number n as :

A
rnn2, En1n2
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B
rnn, En1n
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C
rnn, Enn
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D
rnn, Enn
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Solution

The correct option is D rnn, Enn
Let force of attraction towards the centre is F, then

F=dUdr=kr=mv2r=centripetal force

mvr=nh2π[Bohr's Quantization rule]

So, m2v2m=kr2(nh2πr)21m=kr2

r2n

rn

Also E=K.E+P.E.

E=12kr2+12mv2=12kr2+12×(kr2)

=kr2n[as k is constant and r2n]

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