The equation of the locus of the point whose distance from the point P and the line AB are equal, is
A
x2+9y2+6xy−54x+62y−241=0
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B
9x2+9y2−6xy−54x−62y−241=0
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C
x2+y2−2x+27x−31y−120=0
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D
9x2+y2−6xy−54x−62y+241=0
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Solution
The correct option is D9x2+y2−6xy−54x−62y+241=0 Equation of AB=y−0=−13(x−3) x+3y−3=0 |x+3y−3|2=10[(x−3)2+(y−4)2]
(Look at coefficient of x2 & y2 in the answers)