You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Addition Reaction

Compound A of...

Question

Compound A of molecular formula $C_{4} H_{10} O$ on treatment with Lucas reagent at room temperature gives compound B. When compound B is heated with alcoholic $K O H$ , it gives isobutene. Compound A and B are respectively:

Butan-2-ol and 2-Chlorobutane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2-Methyl-1-propanol and 1-Chloro-2-methylpropane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2-Methyl-1-propanol and 2-Methyl-2-chloropropane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2-Methyl-2-propanol and 2-Methyl-2-chloropropane

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 2-Methyl-2-propanol and 2-Methyl-2-chloropropane
Degree of unsaturation of $(C_{4} H_{10} O) = \frac{2 C + 2 - H}{2}$
$(D U) = \frac{2 \times 4 + 2 - 10}{2} = 0$
It means compound does not have any double bond or ring. Since it gives lucas test which indicates it should be an alcohol so compound A must be $3^{\circ}$ alcohol.

Reaction involved is given as:

Suggest Corrections

Similar questions

Q. Compound

^{'} A^{'}

of molecular formula

C_{4} H_{10} O

on treatment with Lucas reagent at room temperature gives compound

^{'} B^{'}

. When compound

^{'} B^{'}

is heated with alcoholic

K O H

, it gives isobutene. Compound

^{'} A^{'}

and

^{'} B^{'}

are respectively:

Q. A compound A having molecular formula

C_{4} H_{9} B r

on reaction with alcoholic

K O H

gives a compound B. Bromination of B gives compound C. compound C on treatment with soda lime gives a gaseous compound D. The gas D when passed through ammonical silver nitrate solution forms white precipitate. Identify A, B, C and D and write the reactions involved.

Q. The organic compound A of molecular formula

C_{2} H_{6} O

liberates hydrogen gas with sodium metal. A gives B of formula

C_{4} H_{10} O

, when it reacts with concentrated

H_{2} S O_{4}

at 413K. At 443K with concentrated

H_{2} S O_{4}

A gives compound C of formula

C_{2} H_{4}

. This compound C decolourises bromine water. What are A, B, and C?

Q. Ethanoic acid on heating with ammonia forms compound

A

which on treatment with bromine and sodium hydroxide gives compound

B

. Compound

B

on treatment with

N a N O_{2} / d i l . H C l

gives compound

C

. The compounds

A, B

and

C

respectively are:

An organic compound (A) on reduction gives compound (B). (B) on treatment with CHCl₃ and alcoholic KOH gives (C). (C) on catalytic reduction gives N - methyl aniline. The compound 'A' is

Join BYJU'S Learning Program

Compound A of molecular formula C4H10O on treatment with Lucas reagent at room temperature gives compound B. When compound B is heated with alcoholic KOH, it gives isobutene. Compound A and B are respectively:

Compound A of molecular formula $C_{4} H_{10} O$ on treatment with Lucas reagent at room temperature gives compound B. When compound B is heated with alcoholic $K O H$ , it gives isobutene. Compound A and B are respectively: