If - - are the roots of the equation ax2 - bx - c - 0- then-a- -b-a- -b-1 is equal to

Α +β = ba,αβ =Ca,α ^2+β ^2=b^2 2aca^2 Now, αaβ +b+βaα +b= 2a ...

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If α ,β are t...

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If $α, β$ are the roots of the equation $a x^{2} + b x + c = 0$ , then $\frac{α}{a β + b} + \frac{β}{a α + b} = 1$ is equal to

- \frac{2}{a}

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\frac{2}{b}

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\frac{2}{c}

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\frac{2}{a}

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