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Question

N=4!+5!+6!.........200!. Find the last two digits of N.

A
00
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B
13
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C
04
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D
54
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Solution

The correct option is C 04

From 10!, the factorials end with 00 as the last two digits. We thus need to find the last two digits from 4! To 9! only.

4!+5!+6!....9!=24+120+720+5040+40320+362880=___04.


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