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Question

Which of the following is true for 0<x<1?

A
14<f(x)<1
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B
0<f(x)<
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C
<f(x)<0
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D
12<f(x)<12
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Solution

The correct option is C <f(x)<0
d2ydx22dydx+yex

exd2ydx22exdydx+exy1

d2dx2(yex)1

yex is concave up

Hence, <f(x)<0

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