Match the compounds given in Column-I with the products formed and the reaction type when they react with hypo given in Column-II and select the correct answer using the code given below :

Column I
(Compound)

Column-II
(Product with Hypo)

(P)

$C u S O_{4}$

(1)

$N a_{2} S_{4} O_{6}$

(Q)

$H C l$

(2)

$S$

(R)

$H_{2} S O_{4}$

(3)

$S O_{2}$

(S)

$I_{2}$

(4)

Oxidised

(5)

Reduced

P(4); Q(1, 5); R(2, 3); S(2)

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P(1, 4); Q(2, 3); R(2, 3); S(1, 5)

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P(3, 5); Q(1, 3); R(2, 4, 5); S(1, 2, 3)

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P(2, 4); Q(3, 4); R(1, 4); S(2, 3)

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Solution

The correct option is B P(1, 4); Q(2, 3); R(2, 3); S(1, 5)
$C u S O_{4} N a_{2} S_{2} O_{3} - ---- \to N a_{4} [C u_{6} (S_{2} O_{3})_{5}] + N a_{2} S_{4} O_{6}$
$H C l N a_{2} S_{2} O_{3} - ---- \to N a C l + S O_{2} + S$
$H_{2} S O_{4} N a_{2} S_{2} O_{3} - ---- \to N a_{2} S O_{4} + S O_{2} + S$
$I_{2} N a_{2} S_{2} O_{3} - ---- \to N a_{2} S_{4} O_{6} + N a I$

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	Column I (Compound)		Column-II (Product with Hypo)
(P)	$C u S O_{4}$	(1)	$N a_{2} S_{4} O_{6}$
(Q)	$H C l$	(2)	$S$
(R)	$H_{2} S O_{4}$	(3)	$S O_{2}$
(S)	$I_{2}$	(4)	Oxidised
		(5)	Reduced

The correct option is B P(1, 4); Q(2, 3); R(2, 3); S(1, 5)CuSO4Na2S2O3−−−−−→Na4[Cu6(S2O3)5]+Na2S4O6 HClNa2S2O3−−−−−→NaCl+SO2+S H2SO4Na2S2O3−−−−−→Na2SO4+SO2+S I2Na2S2O3−−−−−→Na2S4O6+NaI