In the following reaction , $B$ is

salicylic acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2,4,6-tribromoaniline

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

phenol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

benzoic acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2,4,6-tribromoaniline
When aniline $(A)$ undergoes bromination, 2,4,6-tribromobenzene $(B)$ is formed . Then $B$ reacts with $N a N O_{2} / H C l$ , it forms diazonium salt $(C)$ and $C$ reacts with ethanol to form 2, 4, 6-tribromoaniline on boiling. The reaction is shown below:

Suggest Corrections

Similar questions

A^{+} + B \to A + B^{+}

B

A B r o m i n a t i o n - ------- \to B N a N O_{2} / H C l - ------- \to C B o i l i n g - ---- \to C_{2} H_{5} O H

C H_{3} C H_{2} C O O H R e d P - -- \to B r_{2} A A l c . K O H - ----- \to H^{+} B

A^{+} + B \to A + B^{+}

Join BYJU'S Learning Program