CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A stone is thrown vertically upwards with an initial velocity of 25 m/s. The maximum height reached by the stone is
[Take g=10 m/s2]

A
11.5 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20.15 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
31.25 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5.75 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 31.25 m
When the stone reaches the highest point, its velocity becomes zero.
v=0
Also,
u=25 m/s and
a=g=10 m/s2
Applying, v2=u2+2as
02=(25)2+2×(10)×s
or, s=25×2520 s=31.25 m

flag
Suggest Corrections
thumbs-up
119
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Second Law of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon