Question

The fore bearing of a line CD is ${324}^0{45}^{\prime }$, The back bearing of the line is:

• A. ${54}^0{45}^{\prime }$
• B. ${234}^0{45}^{\prime }$
• C. ${35}^0{15}^{\prime }$
• D. ${144}^0{45}^{\prime }$

Answer 1

The correct option is D

${144}^0{45}^{\prime }$

(a)

If the fore bearing of a line is given as whole circle bearing.


$\text{F.B of line CD =}{324}^0{45}^{\prime }$

$\text{Since F.B >}{180}^0$

$\text{B.B of line =}{324}^0{45}^{\prime }-{180}^0={144}^0{45}^{\prime }$

Note: Fore bearing (F.B) = Bearing of a line in the direction of progress.

Back bearing (B.B) = Bearing of a line opposite direction of progress.