Question

Two fair dice are rolled together, one of the dice showing 4 then the probability that the other is showing 6 is

• A. $\frac{1}{36}$
• B. $\frac{2}{11}$
• C. $\frac{1}{6}$
• D. $\frac{1}{18}$

Answer 1

The correct option is B $\frac{2}{11}$

$n\left(E\right)=2$

$n\left(S\right)=11$

$P\left(E\right)=\frac{2}{11}$

$S=\left\{\right(4,1),(4,2),(4,3),(4,4),(4,5),(4,6);(6,4),(5,4),(3,4),(2,4),(1,4\left)\right\}$

$E=\left\{\right(4,6),(6,4\left)\right\}$