Upon treatment with ammoniacal $H_{2} S$ , the metal ion that precipitates as a sulfide is

F e (I I I)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A l (I I I)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Z n (I I)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

M g (I I)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $Z n (I I)$
Upon treatment with ammoniacal $H_{2} S, Z n^{2 +}$ ion gets precipitated as $Z n S . F e^{3 +}$ ion and $A l^{3 +}$ ions also get precipitated as hydroxides but not as sulphide.

Suggest Corrections

Similar questions

Q. Upon treatment with ammoniacal

H_{2} S

, the metal ion that precipitates as a sulfide is:

Upon treatment with ammoniacal

H_{2} S

, the metal ion solutions that precipitates as sulphide is ________.

1. Fe(III)

2. Zn(II)

Q. Upon treatment with ammonical

H_{2} S

, the metal ion that precipitates as a sulphide is:

A metallic carbide on treatment with water gives a colourless gas which burns readily in air and which gives a precipitate with ammoniacal silver nitrate solution. Gas evolved is

Q. Assertion :The test with the sulfide ion must be conducted in the presence of dilute HCl. Reason: Its purpose is to keep the sulfide ion concentration at a required minimum, so as to allow the precipitation of 2nd group cations alone.

Join BYJU'S Learning Program

Upon treatment with ammoniacal H2S, the metal ion that precipitates as a sulfide is

The correct option is C Zn(II)Upon treatment with ammoniacal H2S,Zn2+ ion gets precipitated as ZnS.Fe3+ ion and Al3+ ions also get precipitated as hydroxides but not as sulphide.

Upon treatment with ammoniacal $H_{2} S$ , the metal ion that precipitates as a sulfide is

The correct option is C $Z n (I I)$
Upon treatment with ammoniacal $H_{2} S, Z n^{2 +}$ ion gets precipitated as $Z n S . F e^{3 +}$ ion and $A l^{3 +}$ ions also get precipitated as hydroxides but not as sulphide.