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Question

# In Li++ electron in first Bohr orbit is excited to a level by a radiation of wavelength X. When the ion gets deexcited to the ground state in all possible ways (including intermediate emissions), a total of six spectral lines are observed. What is the value of λ ?

A
11.4 nm
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B
12.3 nm
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C
10.8 nm
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D
9.4 nm
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Solution

## The correct option is C 10.8 nmSpectral lines obtained on account of trnsition from nth orbit to various lower orbits is =n(n−1)2 ⇒6=n(n−1)2 ⇒n=4 ΔE=hcλ=−Z2n2(13.6 eV) ⇒1λ=Z2(13.6 eVhc)(1n22−1n21) ⇒1λ=(13.6)(3)2hc[1−116]eV ⇒λ=1242×16(13.6)×(9)(15) nm≈10.8 nm. Hence option (D) is correct.

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