Consider the following statements and select the incorrect statement out of the following.

F e^{+}

and

F e^{+}

ions form dirty green and reddish brown coloured ppt with

N a o h

, neither of which dissolved in the excess ogf the reagent.

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C r^{3 +}

and

N i^{2 +}

both form green precipitates with

N a O H

, the precipitate of the former dissolves in excess reagent but that of the latter does not.

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A g^{+}

and

H g^{+}

both form brownish black ppt with

N a O H

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A l^{+}

and

Z n^{+}

both form gelatinous white ppt with

N a O H

, the precipitate of the former dissolves in excess reagent but that of the latter does not.

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Solution

The correct option is D $A l^{+}$ and $Z n^{+}$ both form gelatinous white ppt with $N a O H$ , the precipitate of the former dissolves in excess reagent but that of the latter does not.
$C r {(O H)}_{3} O H - ⟶ [C r {(O H)}_{4}] -$
(green) (green)

$N i {(O H)}_{2} O H^{-} ⟶ X$
(green)

$A g^{+} O H^{-} ⟶ A g_{2} O O H^{-} ⟶$
$(B r o w n i s h b l a c k)$

$H g^{+} O H^{-} ⟶ H g_{2} O O H^{-} ⟶$
$(B r o w n i s h b l a c k)$

$F e {(O H)}_{2} O H^{-} ⟶ X$
$(g r e e n)$

$F e {(O H)}_{3} O H^{-} ⟶ X (r e d d i s h b r o w n)$

$A I {(O H)}_{3} O H^{-} ⟶ {[A I {(O H)}_{4}]}_{4}^{-}$

$Z n {(O H)}_{2} O H^{-} ⟶ {[Z n {(O H)}_{4}]}_{4}^{2 -}$

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