Question

$Mn{O}_4^{-}$ is of intense pink colour, though $Mn$ is in $+7$ oxidation state. It is due to,

• A. Charge transfer when $Mn$ gives its electrons to oxygen
• B. None of the above
• C. Oygen gives colour to it
• D. Charge transfer when oxygen gives its electrons to $Mn$ to making it $Mn\left(VI\right)$ hence coloured

Answer 1

The correct option is D Charge transfer when oxygen gives its electrons to $Mn$ to making it $Mn\left(VI\right)$ hence coloured

$Mn$ is in $(+7)$ oxidation state it has no unpaired electron it is in $d^0$ state . So Charge transfer from ligand to metal occurs i.e from oxygen to $Mn$ and reduce it to $+7to+6$ hence intense pink colour shown.