If - - be the roots of x2-ax-1-b-0- then the value of 1- 2-a-1- 2-a-2a-b is

From given equation, α +β =a, αβ =a+b Now, 1α ^2 aα+1β ^2 aβ=1α (α a)+1β (β a)= 1αβ 1αβ= 2αβ= 2(a+b) Hence, 2α ^2 aα+1β ^2 aβ+2a+b=0 ...

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If α ,β be th...

Question

If $α, β$ be the roots of $x^{2} - a (x - 1) + b = 0,$ then the value of
$\frac{1}{α^{2} - a α} + \frac{1}{β^{2} - a β} + \frac{2}{a + b} i s$

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\frac{2}{a + b}

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\frac{4}{a + b}

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\frac{1}{a + b}

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