Match list I with list II:

List I
(Metal ion) List II
(Group in qualitative analysis)

(a) $M n^{2 +}$ (i) Group III

(b) $A s^{3 +}$ (ii)Group IIA

(c) $C u^{2 +}$ (iii) Group IV

d) $A l^{3 +}$ (iv) Group IIB

(a) - (i v); (b) - (i i); (c) - (i i i); (d) - (i)

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(a) - (i); (b) - (i v); (c) - (i i); (d) - (i i i)

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(a) - (i); (b) - (i i); (c) - (i i i); (d) - (i v)

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(a) - (i i i); (b) - (i v); (c) - (i i); (d) - (i)

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Solution

The correct option is D $(a) - (i i i); (b) - (i v); (c) - (i i); (d) - (i)$
Match list I with list II:

List I
(Metal ion) List II
(Group in qualitative analysis)

$M n^{2 +}$ Group IV

$A s^{3 +}$ Group IIB

$C u^{2 +}$ Group IIA

$A l^{3 +}$ Group III

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Similar questions

If N is selected in GROUP I, who must be selected in GROUP II?

I) M II) P III)S IV) R

A. Pressure group	I. Narmada Bachao Andolan
B. Long-term movement	II. Asom Gana Parishad
C. Single issue movement	III Women's movement
D. Political party	IV Fertilizer dealers association

S n^{2 +}, H g_{2}^{2 +}, P b^{2 +}, Z n^{2 +}, C u^{2 +}, C r^{3 +}, A s^{3 +}, M g^{2 +}, S b^{3 +}

Match list-I with list-II and select the correct answer using the codes given below -

List-I List-II

Ion Radius (in pm)

(I) $L i^{+}$ (a) 216

(II) $N a^{+}$ (b) 195

(III) $B r^{-}$ (c) 60

(IV) $I^{-}$ (d) 95

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List I (Metal ion)	List II (Group in qualitative analysis)
(a) $M n^{2 +}$	(i) Group III
(b) $A s^{3 +}$	(ii)Group IIA
(c) $C u^{2 +}$	(iii) Group IV
d) $A l^{3 +}$	(iv) Group IIB

List I (Metal ion)	List II (Group in qualitative analysis)
$M n^{2 +}$	Group IV
$A s^{3 +}$	Group IIB
$C u^{2 +}$	Group IIA
$A l^{3 +}$	Group III