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B
4.896 eV
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C
0.489 eV
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D
48.96 eV
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Solution
The correct option is A 489.6 eV Total energy in the first Bohr orbit is E1=13.6×Z2eV =−13.6×36eV=−489.6eV ∴ K.E. of electron in the first Bohr orbit = – Total energy
= +489.6 eV