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Standard XII

Chemistry

Oxidizing Nature of Sulphuric Acid

Arrange the f...

Question

Arrange the following in the decreasing order of boiling point:
(i) $C_{2} H_{5} O H$
(ii) $(C H_{3})_{2} N H$
(iii) $C_{2} H_{5} N H_{2}$

i i i > i i > i

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i > i i > i i i

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i > i i i > i i

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i i > i > i i i

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Solution

The correct option is C $i > i i i > i i$
All the given compounds have intermolecular hydrogen bonding due to which their boiling points are higher. $C_{2} H_{5} O H$ possesses the strongest hydrogen bonding because the $O$ is more electronegative than $N$ . Therefore, it has the highest boiling point.

In $(C H_{3})_{2} N H$ and $C_{2} H_{5} N H_{2}$ , the second one has two hydrogen atoms. Because of this, $C_{2} H_{5} N H_{2}$ can make better hydrogen bonding and thus have higher boiling point. Thus, the correct order is $i > i i i > i i$
Hence, the correct option is (c)

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Similar questions

Q. Arrange the following in the decreasing order of boiling point:
(i)

C_{2} H_{5} O H

(ii)

(C H_{3})_{2} N H

(iii)

C_{2} H_{5} N H_{2}

Arrange the following in the decreasing order of boiling point:

C_{2} H_{5} O H

ii)

(C H_{3})_{2} N H

iii)

C_{2} H_{5} N H_{2}

Q. Arrange the following in the increasing order of boiling point:

(i) $C_{2} H_{5} O H$

(ii) $(C H_{3})_{2} N H$

(iii) $C_{2} H_{5} N H_{2}$

Q. Arrange the following in increasing order of boiling points:

(C H_{3})_{3} N, C_{2} H_{5} O H

and

C_{2} H_{5} N H_{2}

Arrange the following:

(i) In the decreasing order of the $p K_{b}$ values
$C_{2} H_{5} N H_{2}, C_{6} H_{5} N H C H_{3}, (C_{2} H_{5})_{2} N H$ and $C_{6} H_{5} N H_{2}$

(ii) In increasing order of basic strength:
$C_{6} H_{5} N H_{2}, C_{6} H_{5} N (C H_{3})_{2}, (C_{6} H_{5})_{2} N H a n d C H_{3} N H_{2}$

(iii) In increasing order of basic strength:
(a) Aniline, p-nitroaniline and p-toluidine
(b) $C_{6} H_{5} N H_{2}, C_{6} H_{5} N H C H_{3}, C_{6} H_{5} C H_{2} N H_{2}$

(iv) In decreasing order of basic strength in gas phase :

$C_{2} H_{5} N H_{2}, (C_{2} H_{5})_{2} N H, (C_{2} H_{5})_{3} N a n d N H_{3}$

(v) In increasing order of boiling point:

$C_{2} H_{5} O H, (C H_{3})_{2} N H, C_{2} H_{5} N H_{2} .$

(vi) In increasing order of solubility in water :

$C_{6} H_{5} N H_{2}, (C_{2} H_{5})_{2} N H, C_{2} H_{5} N H_{2} .$

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Arrange the following in the decreasing order of boiling point: (i) C2H5OH (ii) (CH3)2NH (iii) C2H5NH2

Arrange the following in the decreasing order of boiling point:
(i) $C_{2} H_{5} O H$
(ii) $(C H_{3})_{2} N H$
(iii) $C_{2} H_{5} N H_{2}$