A shop has 50 red bangles and 100 blue bangles- If Seema buys 4-5 of the red bangles and 1-4 of the blue bangles- how many bangles does she buy in all-

Number of red bangles = 50 4/5 of red bangles = 4/5̸1×5̸0̸^10 = 40 Number of blue bangles = 100 1/4 of blue bangles bought= 1/4̸1×1̸0̸0̸^25= 5 ∴ Total number ...

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Standard V

Mathematics

Weight and Its Measurement

A shop has 50...

Question

A shop has 50 red bangles and 100 blue bangles. If Seema buys $\frac{4}{5}$ of the red bangles and $\frac{1}{4}$ of the blue bangles, how many bangles does she buy in all?

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Solution

The correct option is A 65
Number of red bangles = 50
$\frac{4}{5}$ of red bangles = $\frac{4}{/ 51} \times / 50^{10} = 40$

Number of blue bangles = 100
$\frac{1}{4}$ of blue bangles bought= $\frac{1}{/ 41} \times / 100^{25} = 5$

$∴$ Total number of bangles = 40 + 25 = 65

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A shop has 50 red bangles and 100 blue bangles. If Seema buys 45 of the red bangles and 14 of the blue bangles, how many bangles does she buy in all?

The correct option is A 65Number of red bangles = 50 45 of red bangles = 4/51×/5010=40 Number of blue bangles = 100 14 of blue bangles bought= 1/41×/10025=5 ∴ Total number of bangles = 40 + 25 = 65

A shop has 50 red bangles and 100 blue bangles. If Seema buys $\frac{4}{5}$ of the red bangles and $\frac{1}{4}$ of the blue bangles, how many bangles does she buy in all?

The correct option is A 65
Number of red bangles = 50
$\frac{4}{5}$ of red bangles = $\frac{4}{/ 51} \times / 50^{10} = 40$

Number of blue bangles = 100
$\frac{1}{4}$ of blue bangles bought= $\frac{1}{/ 41} \times / 100^{25} = 5$

$∴$ Total number of bangles = 40 + 25 = 65