What would be the electrode potential for the half cell reaction at pH - 5-2H2O- O2-4H-4e-Ered0-1-23 VR-8-314 J mol-1K-1- Temperature-298 K- oxygen under std- atm- pressure of 1 bar

2H_2O→ O_2+4H^⊕+4e^ ; It is a oxidation reaction so nbsp; E^0= 1.23 V By nernst equation, nbsp; E=E^0 0.05914log[H^+]^4 E = 1.23+0.0591× pH E = 1.23+0.0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Ideal Gas Equation

What would be...

Question

What would be the electrode potential for the half cell reaction at pH = 5?
$2 H_{2} O \to O_{2} + 4 H^{\oplus} + 4 e^{-}; E_{r e d}^{0} = 1.23 V$
( $R = 8.314 J {mol}^{- 1} K^{- 1};$ Temperature=298 K; oxygen under std. atm. pressure of 1 bar)

-0.93

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-0.934

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

$2 H_{2} O \to O_{2} + 4 H^{\oplus} + 4 e^{-};$
It is a oxidation reaction so
$E^{0} = - 1.23 V$
By nernst equation,
$E = E^{0} - \frac{0.0591}{4} l o g [H^{+}]^{4}$

$E = - 1.23 + 0.0591 \times p H$

$E = - 1.23 + 0.0591 \times (5)$

$E = - 0.93 V$

Suggest Corrections

Similar questions

Q. What will be the electrode potential for the given half cell reaction at pH= 5?

2 H_{2} O \to O_{2} + 4 H^{+} + 4 e^{-}; E^{\circ} = - 1.23 V

(R= 8.314

J m o l^{- 1} K^{- 1};

temp = 298 K; oxygen under std. atm. Pressure of 1 bar.)

Consider a $70 %$ efficient hydrogen-oxygen fuel cell working under standard conditions at $1 bar$ and $298 K$ . Its cell reaction is

$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l)$
The work derived from the cell on the consumption of $1.0 \times 10^{- 3} mol$ of $H_{2} (g)$ is used to compress $1.00 mol$ of a monoatomic ideal gas in a thermally insulated container. What is the change in the temperature (in K) of the ideal gas?The standard reduction potentials for the two half-cells are given below.
$O_{2} (g) + 4 H^{+} (a q) + 4 e^{-} \to 2 H_{2} O (l), E^{o} = 1.23 V 2 H^{+} (a q) + 2 e^{-} \to H_{2} (g), E^{o} = 0.00 V$
Use $F = 96500 C m o l^{- 1}, R = 8.314 J m o l^{- 1} K^{- 1}$