You visited us 1 times! Enjoying our articles? Unlock Full Access!

Coordination and Oxidation Number

The volume in...

Question

The volume (in mL) of $0.1 M A g N O 3$ required for complete precipitation of chloride ions present in $30 m L$ of $0.01 M$ solution of $[C r (H_{2} O)_{5} C l] C l_{2}$ , as silver chloride is close to

Open in App

Solution

Applying equation,

$N_{1} V_{1} = N_{2} V_{2}$
$0.1 \times V = 2 \times 0.01 \times 30$
$V = \frac{2 \times 30 \times 30}{100 \times 1} = 6$

Suggest Corrections

Similar questions

mL

0.1 M A g N O_{3}

30 mL

0.01 M

[C r (H_{2} O)_{5} C l] C l_{2}

0.1

A g N O_{3}

30 m l

0.01 M

[C r (H_{2} O)_{5} C l] C l_{2}

0.1 M

A g N O_{3}

30

0.01 M

[C r (H_{2} O)_{5} C l] C l_{2}

A g N O_{3}

[C r (H_{2} O)_{6}] C l_{3}

0.1 M A g N O_{3}

0.01 M

[C r (H_{2} O)_{5} C l] C l_{2}

Join BYJU'S Learning Program