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Question

If a and b are vectors such that |a+b|=29 and a×(2ˆi+3ˆj+4ˆk)=(2ˆi+3ˆj+4ˆk)×b , then a possible value of (a+b).(7ˆi+2ˆj+3ˆk) is

A
8
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B
3
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C
3
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D
4
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Solution

The correct option is A 8
a×(2i+3j+4k)+b×(2i+3j+4k)=0

(a+b)×(2i+3j+4k)=0

(a+b=λ(2i+3j+4k))

Given, |a+b|=29

λ=1

So, a+b=2i+3j+4k

Now, (a+b)(7ˆi+2ˆj+3ˆk)=4

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