Match List-I with List-IIList-I-Chemical reactionList-II-Reagent usedaCH3COOCH2CH3- CH3CH2OHiCH3MgBr-H3O-1 equivalentb CH3COOHCH3- CH3CHOiiH2SO4-H2Oc CH3C - N - CH3CHO- iiiDIBAL-H-H2 Od CH3C - N - CH3COCH3iv SnCl2-HCl-H2OChoose the most appropriate match-

(a) Ester get hydrolysed to respective acid and alcohol in presence of sulphuric acid. nbsp; CH_3COOCH_2CH_3 CH_3COOH+CH_3CH_2OH (b) DIBAL H will reduce est ...

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Byju's Answer

Standard XII

Chemistry

Oxidation of Alkenes

Match List-I ...

Question

Match List-I with List-II

List-I
(Chemical reaction) List-II
(Reagent used)

(a) $C H_{3} C O O C H_{2} C H_{3} \to C H_{3} C H_{2} O H$ (i) $C H_{3} M g B r / H_{3} O^{+}$
(1 equivalent)

(b) $C H_{3} C O O H C H_{3} \to C H_{3} C H O$ (ii) $H_{2} S O_{4} / H_{2} O$

(c) $C H_{3} C \equiv N \to C H_{3} C H O$
(iii) $D I B A L - H / H_{2} O$

(d) $C H_{3} C \equiv N \to C H_{3} C O C H_{3}$ (iv) $S n C l_{2}, H C l / H_{2} O$

Choose the most appropriate match.

(a) - (i i i), (b) - (i i), (c) - (i), (d) - (i v)

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(a) - (i v), (b) - (i i), (c) - (i i i), (d) - (i)

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(a) - (i i), (b) - (i v), (c) - (i i i), (d) - (i)

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(a) - (i i), (b) - (i i i), (c) - (i v), (d) - (i)

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Solution

The correct option is D $(a) - (i i), (b) - (i i i), (c) - (i v), (d) - (i)$
(a) Ester get hydrolysed to respective acid and alcohol in presence of sulphuric acid.
$C H_{3} C O O C H_{2} C H_{3} H_{2} S O_{4} - --- \to H_{2} O C H_{3} C O O H + C H_{3} C H_{2} O H$

(b) DIBAL-H will reduce esther group to aldehyde.
$C H_{3} C O O C H_{3} D I B A L - H - ------ \to H_{2} O C H_{3} - C H O + C H_{3} O H$

(c)
This reaction is called stephen reaction. It involves the preparation of aldehydes from nitriles using tin(II) chloride, hydrochloric acid and quenching the resulting iminium salt with water. During the synthesis, ammonium chloride is also produced.

(d) When nitriles react with grignard reagent $R^{-}$ from the grignard will undergo nulceophilic addtion reaction to form imine product.
Imine will undergo hydrolysis to form keto product.

So, the correct match is
$(a) - (i i), (b) - (i i i), (c) - (i v), (d) - (i)$

Cyanides can also be converted to aldehydes by $D I B A L - H / H_{2} O$ as well.

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List - I Chemical reaction	List - II Name of process
I. $4 N H_{3} + 5 O_{2} 800^{\circ} C / P t - ----- \to 4 N O + 6 H_{2} O$	( a ) Contact process
II. $4 H C l + O_{2} 3230^{\circ} C / C u C l_{2} - -------- \to 450 - 500^{\circ} / V_{2} O_{5} 2 C l_{2} + 2 H_{2} O$	( b ) Ostwald's process
III. $2 S O_{2} + O_{2} \to 2 S O_{3}$	( c ) Deacon's process
IV. $2 N_{2} + 3 H_{2} F e + M o - --- \to 2 N H_{3}$	( d ) Haber's proces

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$C a {(O C l)}_{2}$ (i) Antacid

$C a S O_{4} \cdot \frac{1}{2} H_{2} O$ (ii) Cement

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Q. Match the items in List-I with the items in List-II
List-I : List-II

Q. Match List-I with List-II

List-I	List-II
(a) $N a O H$	(i) Acidic
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Q. Match List-I with List-II.

	List-I		List-II
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List-I (Chemical reaction)	List-II (Reagent used)
(a) $C H_{3} C O O C H_{2} C H_{3} \to C H_{3} C H_{2} O H$	(i) $C H_{3} M g B r / H_{3} O^{+}$ (1 equivalent)
(b) $C H_{3} C O O H C H_{3} \to C H_{3} C H O$	(ii) $H_{2} S O_{4} / H_{2} O$
(c) $C H_{3} C \equiv N \to C H_{3} C H O$	(iii) $D I B A L - H / H_{2} O$
(d) $C H_{3} C \equiv N \to C H_{3} C O C H_{3}$	(iv) $S n C l_{2}, H C l / H_{2} O$

Match List-I with List-II List-I (Chemical reaction) List-II (Reagent used) (a)CH3COOCH2CH3→CH3CH2OH (i)CH3MgBr/H3O+ (1 equivalent) (b) CH3COOHCH3→CH3CHO (ii)H2SO4/H2O (c) CH3C≡N→CH3CHO (iii)DIBAL−H/H2O (d) CH3C≡N→CH3COCH3 (iv) SnCl2,HCl/H2O Choose the most appropriate match.