Question

The alternating current is given by $i=\{\sqrt{42}\sin \left(\frac{2\pi }{T}t\right)+10\}\text{A}$. The r.m.s value of this current is $\text{A}$

• A. 11
• B. 11.0

Answer 1

Answer: (A), (B)

The rms value of the current is :
$I_{rms}=\sqrt{(I_1{)}_{rms}^2+(I_2{)}_{rms}^2}$
$I_{rms}=\sqrt{{\left(\frac{\sqrt{42}}{\sqrt{2}}\right)}^2+{10}^2}$
$I_{rms}=\sqrt{121}=11\text{A}$