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Find the inte...

Question

Find the integral:
$\int (4 e^{3 x} + 1) d x$

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Solution

$\int (4 e^{3 x} + 1) d x$
$= \int (4 e^{3 x} + 1) d x$
$= 4 \int e^{3 x} d x + \int d x$
$= \frac{4 e^{3 x}}{3} + x + C$

Where $C$ is constant of integration

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