Four fair dice D1,D2,D3 and D4, each having six faces numbered 1,2,3,4,5 and 6, are rolled simultaneously. The probability that D4 shows a number appearing on one of D1,D2 and D3 is
A
127216
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B
91216
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C
108216
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D
125216
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Solution
The correct option is B91216 Required probability
= Getting equal number on two dice + equal number on three dice + equal number on four dice