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Question

A series LCR circuit of R=5 Ω, L=20 mH and C=0.5 μF is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is _____ ×102 W.

A
125.0
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B
125
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Solution


At resonance condition,

Z=R (XLXC=0)

irms=VZ=VR

So, the power dissipated,

P=V2R=250×2505=125×102 W

Correct answer:125

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