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Standard XII

Physics

Torque about a Point

A wire of are...

Question

A wire of area of cross-section $10^{- 6} m^{2}$ is increased in length by $0.1 %$ . The tension produced is $1000 N$ . The Young’s modulus of wire is

10^{11} N / m^{2}

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10^{9} N / m^{2}

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10^{10} N / m^{2}

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10^{12} N / m^{2}

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Solution

The correct option is D $10^{12} N / m^{2}$
Given : $T = F = 1000 N$
$Δ L = \frac{0.1 L}{100}$
We know that,
$Y = \frac{F L}{A Δ L} = \frac{1000 \times 100}{10^{- 6} \times 0.1} = 10^{12} N / m^{2}$

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A wire of area of cross-section 10−6m2 is increased in length by 0.1%. The tension produced is 1000 N. The Young’s modulus of wire is

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A wire of area of cross-section $10^{- 6} m^{2}$ is increased in length by $0.1 %$ . The tension produced is $1000 N$ . The Young’s modulus of wire is

The correct option is D $10^{12} N / m^{2}$
Given : $T = F = 1000 N$
$Δ L = \frac{0.1 L}{100}$
We know that,
$Y = \frac{F L}{A Δ L} = \frac{1000 \times 100}{10^{- 6} \times 0.1} = 10^{12} N / m^{2}$