A solution containing cupric ions is allowed to react with potassium iodide. Select the incorrect option.

The hypo solution convert the triiodide ions to iodide ions

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The colour the precipitate obtained becomes visible if hypo solution is added

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White coloured precipitate of cupric iodide is obtained

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The solution is intensely brown in colour to formation of triiodide ions

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Solution

The correct option is C White coloured precipitate of cupric iodide is obtained
$l_{3}^{-} + N a_{2} S_{2} O_{3} \to l^{-} + S_{4} O_{6}^{2 -}$

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H_{2} S O_{4}

Lead nitrate reacts with potassium iodide to form a yellow precipitate of.

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