In a solid, $P$ atoms form $F C C, Q$ atoms are present in alternate edge centres, $R$ in alternate tetrahedral voids. If $P$ atoms on the two face centres are replaced by $X$ atoms, then the formula of the compounds is

P_{3} Q_{2} R_{4} X

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P_{2} Q_{2} R_{3} X_{2}

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P_{3} Q R_{4} X

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P_{4} Q R_{4} X_{2}

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Solution

The correct option is C $P_{3} Q R_{4} X$
Alternate $T V = 4$

Alternate edge centres $= 4$

Original crystal is

$P_{4} Q_{1} R_{4}$

After replacement of $P$ atoms

$P_{3} Q R_{4} X$

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In a solid, P atoms form FCC, Q atoms are present in alternate edge centres, R in alternate tetrahedral voids. If P atoms on the two face centres are replaced by X atoms, then the formula of the compounds is

The correct option is C P3QR4XAlternate TV=4 Alternate edge centres =4 Original crystal is P4Q1R4 After replacement of P atoms P3QR4X

In a solid, $P$ atoms form $F C C, Q$ atoms are present in alternate edge centres, $R$ in alternate tetrahedral voids. If $P$ atoms on the two face centres are replaced by $X$ atoms, then the formula of the compounds is

The correct option is C $P_{3} Q R_{4} X$
Alternate $T V = 4$

Alternate edge centres $= 4$

Original crystal is

$P_{4} Q_{1} R_{4}$

After replacement of $P$ atoms

$P_{3} Q R_{4} X$