Question

STATEMENT-1 : Let $y=f\left(x\right)=\frac{x+2007}{2008x-1}$ then $x=f\left(y\right)$.
and
STATEMENT-2 : A function $f$ defined by $f\left(x\right)=\frac{ax+d}{cx+d}$ is invertible if $a+d=0$.

• A. Both statement I and statement II are correct and statement II is the correct explanation of statement I
• B. Statement II is correct but statement I is incorrect
• C. Statement I is correct but statement II is incorrect
• D. Both statement I and statement II are correct but statement II is not the correct explanation of statement I

Answer 1

The correct option is A Both statement I and statement II are correct and statement II is the correct explanation of statement I

$f\left(x\right)=\frac{ax+b}{cx+d}$ is invertible if $a+d=0$