N=9876543298765432.........82 digits. Find the remainder when N is divided by 34?
option d
Use Divisibility Rules
34 = 17 *2
So we should use the divisibility test of 17 ( Compartmentalization method - taking 8 digits at a time (Sum of digits at odd places taken 8 at a time- Sum of digits at even places taken 8 at a time)
Combine 8 digits together, 9876......80 digits*100 + 98 :
There will be equal number of groups (of 8 digits taken at a time) at odd places and even
Places in 9876.......80 digits*100.
So Sum of groups at odd places - Sum of groups at even places = 0
Therefore first part is divisible by 17. It is also divisible by 2, as 100 is divisible by 2.Hence, we only need to find the remainder when 98 is divided by 34
Remainder= 30