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B
n
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C
n3(2n+3)2
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D
n3(2n2+12n+13)
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Solution
The correct option is Dn3(2n2+12n+13) Sum of infinit terms, Sn=a1−r=n1−n+12n+1=2n+1 S1Sn+S2Sn−1+...+SnS1 =∑nk=1SkSn−k+1 =∑k=1(2k+1)(2n+3−2k) =n3(2n2+12n+13)