N atoms of a radioactive element emit n number - particle per second- Mean life of the elements in second is -

The correct option is B Nn Number of disintegrations per second= dN/dt = n = N #955; #955; = n/N , #160;where #955; is the decay constantMean life ...

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Standard XII

Physics

Nuclear Force

N atoms of a ...

Question

$N$ atoms of a radioactive element emit $n$ number $α$ - particle per second. Mean life of the elements
in second is :

\frac{n}{N}

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\frac{N}{n}

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0693

\frac{N}{n}

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\frac{n}{N}

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Solution

The correct option is B $\frac{N}{n}$
Number of disintegrations per second= dN/dt = n = Nλ

λ = n/N , where λ is the decay constant

Mean life = 1/λ = N/n

Option B is correct.

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N atoms of a radioactive element emit n number α- particle per second. Mean life of the elements in second is :

The correct option is B NnNumber of disintegrations per second= dN/dt = n = Nλλ = n/N , where λ is the decay constantMean life = 1/λ = N/nOption B is correct.

$N$ atoms of a radioactive element emit $n$ number $α$ - particle per second. Mean life of the elements
in second is :

The correct option is B $\frac{N}{n}$
Number of disintegrations per second= dN/dt = n = Nλ

λ = n/N , where λ is the decay constant

Mean life = 1/λ = N/n

Option B is correct.