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Question

nC0 - nC1 + nC2 - nC3.............. =


A

0

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B

1

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C

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D

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Solution

The correct option is A

0


consider the binomial expansion of (1+x)n

(1+x)n = nC0 + nC1 x + nC2 x2 + nC3 x3. . . . . .

Put x = - 1

nC0 - nC1 + nC2 - nC3 . . . . . = (11)n = 0


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