n C r - n C r -1-MP PET 1984-A- n-r-rB- n-r-1-rC- n-r-1-rD- n-r-1-r

The correct option is C On simplifying you will get n r+1 r. ...

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Byju's Answer

Standard IX

Mathematics

Inverse of a Function

n C r ÷ n C r...

Question

$^{n} C_{r} \div^{n} C_{r - 1} =$

[MP PET 1984]

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Solution

The correct option is C

On simplifying you will get $\frac{n - r + 1}{r}$ .

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Similar questions

$^{n} C_{r} \div^{n} C_{r - 1}$ =

\frac{^{n} C_{r}}{^{n} C_{r - 1}} = ?

If $^{n} C_{r} +^{n} C_{r + 1} =^{n + 1} C_{x},$ then x =

Q. If ⁿC_r + ⁿC_r_{+ 1} = ^{n +}¹C_x , then x =
(a) r
(b) r − 1
(c) n
(d) r + 1

Let r and n be positive integers such that $1 \leq r \leq n .$ Then prove the following :

(i) $\frac{^{n} C_{r}}{^{n} C_{r - 1}} = \frac{n - r + 1}{r}$
(ii) $n^{n - 1} C_{r - 1} = (n - r + 1)^{n} C_{r - 1}$
(iii) $\frac{^{n} C_{r}}{^{n - 1} C_{r - 1}} = \frac{n}{r}$
(iv) $^{n} C_{r} + 2^{n} C_{r - 1} +^{n} C_{r - 2} =^{n + 2} C_{r}$

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nCr÷nCr−1= [MP PET 1984]

The correct option is C On simplifying you will get n−r+1r.

$^{n} C_{r} \div^{n} C_{r - 1} =$

[MP PET 1984]

The correct option is C

On simplifying you will get $\frac{n - r + 1}{r}$ .