Question

$n$ equal resistances are first connected in series, and then the same $n$ equal resistances are connected in parallel. The ratio of net resistance in series combination to that in parallel combination is

$[$0.77 Mark$]$

• A. $n^2$
• B. $\frac{1}{n^2}$
• C. $n^3$
• D. $n$

Answer 1

The correct option is A $n^2$

When $n$ identical resistances are connected in series, then net resistance is given by
$R_{series}=nR$
Now,When $n$ identical resistances are connected in parallel, then net resistance is given by
$R_{parallel}=\frac{R}{n}$
$\frac{R_{series}}{R_{parallel}}=\frac{nR}{\frac{R}{n}}=n^2$