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Question

n!Evaluate (n-T. when(i) n - 6, r 2(ii) n 9, r-5.

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Solution

The expression is given as n! ( nr )! .

(i)

Substitute 6 for n and 2 for r in the given expression.

n! ( nr )! = 6! ( 62 )! = 6! 4!

To take the common factor from numerator and denominator, factorize the bigger term in factorials.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The above term can be written as,

6×5×4! 4! =6×5 =30

Thus, the value of given expression is 30.

(ii)

Substitute 9 for n and 5 for r in the given expression.

n! ( nr )! = 9! ( 95 )! = 9! 4!

To take the common factor from numerator and denominator, factorize the bigger term in factorials.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The above term can be written as,

9×8×7×6×5×4! 4! =9×8×7×6×5 =15120

Thus, the value of given expression is 15120.


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