' $n$ ' factor for $S O_{2}$ in $F e S_{2} + O_{2} ⟶ F e_{2} O_{3} + S O_{2}$ , is :

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Solution

$F e S_{2} + O_{2} ⟶ F e_{2} O_{3} + S O_{2}$
+2 -1 -1 +4
So, n-factor of $S O_{2} = 4 - (- 1) = 5$ .

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