N-factor of Ba M nO 42 in acidic medium is-A- 5B- NoneC- 3D- 10

The correct option is D 10 In acidic medium, MnO^ _4 → Mn^2+ For each MnO_4^ ion, n factor is 5. Since in Ba(MnO_4)_2, there are two MnO_4^ ions, the n fact ...

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Standard XII

Chemistry

Diagonal Relationship

n-factor of B...

Question

n-factor of $B a (M n O_{4})_{2}$ in acidic medium is:

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Solution

The correct option is C
10

In acidic medium,

$M n O_{4}^{-} \to M n^{2 +}$

For each $M n O_{4}^{-}$ ion, n-factor is 5. Since in $B a (M n O_{4})_{2}$ , there are two $M n O_{4}^{-}$ ions, the n-factor is:

$\Rightarrow 5 \times 2 = 10$

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n-factor of Ba(MnO4)2 in acidic medium is:

The correct option is C 10 In acidic medium, MnO−4→Mn2+ For each MnO−4 ion, n-factor is 5. Since in Ba(MnO4)2, there are two MnO−4 ions, the n-factor is: ⇒ 5×2=10

n-factor of $B a (M n O_{4})_{2}$ in acidic medium is:

The correct option is C
10

In acidic medium,

$M n O_{4}^{-} \to M n^{2 +}$

For each $M n O_{4}^{-}$ ion, n-factor is 5. Since in $B a (M n O_{4})_{2}$ , there are two $M n O_{4}^{-}$ ions, the n-factor is:

$\Rightarrow 5 \times 2 = 10$