n-Factor of $K M n O_{4}$ in neutral medium is:

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Solution

The correct option is D 3
In neutral medium $K M n O_{4}$ forms $M n O_{2}$ $(+ 7$ to $+ 4)$
i.e. it gains $3$ electrons.
So, $n$ -factor= $3$ .

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n-Factor of KMnO4 in neutral medium is:

The correct option is D 3In neutral medium KMnO4 forms MnO2 (+7 to +4)i.e. it gains 3 electrons.So, n-factor= 3.

n-Factor of $K M n O_{4}$ in neutral medium is:

The correct option is D 3
In neutral medium $K M n O_{4}$ forms $M n O_{2}$ $(+ 7$ to $+ 4)$
i.e. it gains $3$ electrons.
So, $n$ -factor= $3$ .