$n -$ factor of $N a C N$ in the change, $N a C N ⟶ N a C N O$ , is:

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Solution

The oxidation number of $C$ in $N a C N$ is $+ 2$ .
The oxidation number of $C$ in $N a C N O$ is $+ 4$ .
The change in the oxidation number of $C$ is $2$ .
The $n -$ factor of $N a C N$ in the change $N a C N ⟶ N a C N O$ is 2.

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